There is a function which takes a float** parameter. I have the values in a variable of type std::vector<std::vector<float>>.
Is it possible to make such a conversion without allocating a temporary float*[] ?
#include <vector>
#include <iostream>
#include <stdlib.h>
#include <time.h>
using namespace std;
void compare(int m, int n, float **score)
{
for(int i=0; i<m; i++)
{
for(int j=0; j<n; j++)
{
score[i][j] = (i*n + j)/100.0;
}
}
}
int main()
{
int m=20, n=5;
vector<float> vec1(n);
vector<vector<float>> vec2;
for(int i=0; i<m; i++)
{
vec2.push_back(vec1);
}
vector<float*> target(vec2.size());
for (int i = 0; i < vec2.size(); ++i)
{
target[i] = &*vec2[i].begin();
}
compare(m, n, target.data());
for(int i=0; i<m; i++)
{
for(int j=0; j<n; j++)
{
cout << vec2[i][j] << "\t";
}
cout << endl;
}
return 0;
}
