the theory of Riemann zeta function and yu-tang Hong in august20,2026discovered the core of all s...

it is easy to proof every function  of the  from is absolutely coverance to zeta(2n)=pi^2n*bn/(2n)!/2^(2n-1),for example,zeta(6)=pi^6/945;zea(8)=pi^8/9450;zeta(10)=pi^10/93555;zeta(12)=691*pi^12/638512875;zeta(14)=14*pi^14/127702575;zeta(16)=3617*pi^16/325641566250;zeta(18)=43867*pi^18/38979295480125;zeta(20)=174611*pi^(20)/1531329465290625;zeta(22)=854513*pi^(22)/73963213173537187.5;zeta (24)=236364091*pi^24/201919571963756521875;zeta(26)=8553103*2*pi^(24)/144228265688387515625;zeta(28)=2*23749461029*pi^28/3952575621190533915703125;zeta(30)=pi^30/t(411761479374835)=1+1/t(19280580074);....... 任意大的zeta function 收敛真值都可以用两个非平凡的零点值来表达。