# 1.声明一个字典保存一个学生的信息，学生信息中包括: 姓名、年龄、成绩(单科)、电话、性别(男、女、不明)
students = [
    {'name': '小明', 'sex': '男', 'age': 17, 'score': 90, 'tel': '110'},
    {'name': '小红', 'sex': '男', 'age': 16, 'score': 78, 'tel': '120'},
    {'name': '小黄', 'sex': '男', 'age': 20, 'score': 58, 'tel': '119'},
    {'name': '蔡徐坤', 'sex': '不明', 'age': 19, 'score': 23, 'tel': '10010'},
    {'name': '小绿', 'sex': '男', 'age': 30, 'score': 67, 'tel': '10001'},
    {'name': '小青', 'sex': '男', 'age': 98, 'score': 59, 'tel': '10008'}
]
# a.统计不及格学生的个数
n = 0
for student1 in students:
    if student1['score'] < 60:
        n += 1
print('不及格人数:', n)
print()

# b.打印不及格学生的名字和对应的成绩
print('不及格学生:')
for student1 in students:
    if student1['score'] < 60:
        print(student1['name'], student1['score'])
print()

# c.统计未成年学生的个数
n = 0
for age in students:
    if age['age'] < 18:
        n += 1
print('未成年:', n)
print()

# d.打印手机尾号是8的学生的名字
for tel1 in students:
    tel2 = int(tel1['tel'])
    if tel2 % 10 == 8:
        print(tel1['name'])
print()

# e.打印最高分和对应的学生的名字
score_max = 0
name1 = 0
for score1 in students:
    if score1['score'] > score_max:
        score_max = score1['score']
        name1 = score1['name']
print(name1)

 # f.将列表按学生成绩从大到小排序
 i = len(students)
 for _ in range(i - 1):
     for num1 in range(i - 1):
         if students[num1]['score'] < students[num1 + 1]['score']:
             students[num1], students[num1 + 1] = students[num1 + 1], students[num1]
 print(students)


# g.删除性别不明的所有学生
for num2 in students[:]:
    if num2['sex'] == '不明':
        students.remove(num2)
print(students)

# 3.用三个列表表示三门学科的选课学生姓名(一个学生可以同时选多门课)
list1 = ['小明', '小红', '小黄', '小蓝', '蔡徐坤']
list2 = ['小黄', '小蓝', '小靛', '小紫', '蔡徐坤']
list3 = ['小靛', '小紫', '王境泽', '真香', '蔡徐坤']
set1 = set(list1)
set2 = set(list2)
set3 = set(list3)
# a. 求选课学生总共有多少人
n = 0
list4 = set1 | set2 | set3
for _ in list4:
    n += 1
print(n)
print('b=================================')
# b. 求只选了第一个学科的人的数量和对应的名字
n = 0
list5 = set1 - set2 - set3
for _ in list5:
    n += 1
print(list5, n)
print('c=================================')
# c. 求只选了一门学科的学生的数量和对应的名字
list6 = (set1 - set2 - set3) | (set2 - set1 - set3) | (set3 - set2 -set1)
n = 0
for _ in list6:
    n += 1
print(list6, n)
print('d=================================')
# d. 求只选了两门学科的学生的数量和对应的名字
d = (set1 | set2 | set3) - list6 - (set1 & set2 & set3)
n = 0
for _ in d:
    n += 1
print(d, n)
print('e================================')
# e. 求选了三门学生的学生的数量和对应的名字
set4 = set1 & set2 & set3
n = 0
for _ in set4:
    n += 1
print(set4, n)