You can create an XML file which has configurations, constants or simple data in it, and in its file properties set Build Action to Embedded Resource.
Then a related model with XmlAttributes is required.

Notice the differences among XmlRoot, XmlAttribue, XmlElement, or this will cause parse errors.

TeamModel.cs

    [XmlRoot("TeamModel")]
    public class TeamModel
    {
        private string _name = string.Empty;

        [XmlAttribute("Name")]
        public string Name
        {
            get { return _name; }
            set { _name = value; }
        }

        private List<MemberModel> aList = new List<MemberModel>();
        [XmlElement("Member")]
        public List<MemberModel> AList
        {
            get { return aList; }
            set { aList = value; }
        }
    }

    public class MemberModel
    {
        private string _firstName = string.Empty;
        [XmlAttribute("FirstName")]
        public string FirstName
        {
            get { return _firstName; }
            set { _firstName = value; }
        }

        private string _lastName = string.Empty;
        [XmlAttribute("LastName")]
        public string LastName
        {
            get { return _lastName; }
            set { _lastName = value; }
        }
    }

TeamModelConfig.xml

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfTeamModel >
  <TeamModel Name="MyTeam">
    <Member FirstName="Zhang" LastName="San"/>
    <Member FirstName="Li" LastName="Si"></Member>
  </TeamModel>
</ArrayOfTeamModel>

Method for XML parse

public T ParseEmbeddedXml<T>(string resourceName)
{
    var result = default(T);
    //use reflection to get executing assembly and its name
    using (Stream stream = Assembly.GetExecutingAssembly().GetManifestResourceStream(
      Assembly.GetExecutingAssembly().GetName().Name.ToString()+"."+resourceName))
    {
        using (StreamReader reader = new StreamReader(stream))
        {
            XmlSerializer xmlSerializer = XmlSerializer.FromTypes(new[] { typeof(T) }).FirstOrDefault();//new XmlSerializer(typeof(T));
            var tempResult = xmlSerializer.Deserialize(reader);
            if (tempResult is T)
                result = (T)tempResult;
        }
    }
    return result;
}