A + B Problem Too

This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.

Sample Input
1 1
8600 8600

Sample Output
no
yes
问题链接：https://vjudge.net/problem/HDU-2101
问题简述：求A+B对86是否整除
问题分析：
1.采用while对多种可能进行
2.加上if判断是否对86整除

程序说明：
程序如下：

#include<iostream>
using namespace std;
int main()
{
    int A, B;
    while (cin >> A>>B)
    {
        if ((A + B) % 86 == 0)
            cout << "yes"<<endl;
        else cout << "no"<<endl;
    }
    system("pause");
}