Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321
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Have you thought about this?
Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!
If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.
Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?
For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
Note:
The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.
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int reverse(int x) {
int res = 0;
while(x){
int tail = x % 10;
x /= 10;
int temp = res * 10 + tail;
if(temp / 10 != res){
return 0;
}
res = temp;
}
return res;
}
实际上这个程序给了我们一个很好的对于越界处理的切入点。判断
temp ／ 10 != res ，要是越界这个等式就会不成立。
