timedelta
from datetime import timedelta
a = timedelta(days=2, hours=6)
b = timedelta(hours=4.5)
c = a + b
c.days
2
c.seconds
37800
c.seconds / 3600
10.5
c.total_seconds() / 3600
58.5
from datetime import datetime
a = datetime(2012, 9, 23)
print(a + timedelta(days=10))
2012-10-03 00:00:00b = datetime(2012, 12, 21)
d = b - a
d.days
89
now = datetime.today()
print(now)
2012-12-21 14:54:43.094063
print(now + timedelta(minutes=10))
2012-12-21 15:04:43.094063
更多功能的日期处理模块dateutil
a = datetime(2012, 9, 23)
a + timedelta(months=1)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'months' is an invalid keyword argument for this functionfrom dateutil.relativedelta import relativedelta
a + relativedelta(months=+1)
datetime.datetime(2012, 10, 23, 0, 0)
a + relativedelta(months=+4)
datetime.datetime(2013, 1, 23, 0, 0)Time between two dates
b = datetime(2012, 12, 21)
d = b - a
d
datetime.timedelta(89)
d = relativedelta(b, a)
d
relativedelta(months=+2, days=+28)
d.months
2
d.days
28
