day18二叉树6
530.二叉搜索树的最小绝对差
class Solution {
public:
int result = INT_MAX;
int num1 = INT_MAX;
int num2 = -100001;
int getMinimumDifference(TreeNode* root) {
if (root == nullptr) {
return result;
}
int left = getMinimumDifference(root->left);
num1 = num2;
num2 = root->val;
result = min(result, num2 - num1);
int right = getMinimumDifference(root->right);
return result;
}
};
优雅版(指针):
class Solution {
private:
int result = INT_MAX;
TreeNode *pre = nullptr;
void traversal(TreeNode *cur) {
if (cur == nullptr) {
return;
}
traversal(cur->left);
if (pre) {
result = min(result, cur->val - pre->val);
}
pre = cur;
traversal(cur->right);
}
public:
int getMinimumDifference(TreeNode* root) {
traversal(root);
return result;
}
};
501.二叉搜索树中的众数
递归法(很巧妙,但是自己没写出来):
class Solution {
private:
int maxCount = 0;
int count = 0;
TreeNode *pre = nullptr;
vector<int> res;
void searchBST(TreeNode *cur) {
if (cur == nullptr) {
return;
}
searchBST(cur->left);
if (pre == nullptr || pre->val != cur->val) {
count = 1;
}
else {
count ++;
}
pre = cur;
if (count == maxCount) {
res.push_back(cur->val);
}
if (count > maxCount) {
maxCount = count;
res.clear();
res.push_back(cur->val);
}
searchBST(cur->right);
}
public:
vector<int> findMode(TreeNode* root) {
searchBST(root);
return res;
}
};
迭代法:
class Solution {
private:
unordered_map<int, int> umap;
void traversal(TreeNode *cur) {
if (cur == nullptr) {
return;
}
traversal(cur->left);
umap[cur->val] ++;
traversal(cur->right);
}
bool static cmp(const pair<int, int> &a, const pair<int, int> &b) {
return a.second > b.second;
}
public:
vector<int> findMode(TreeNode* root) {
traversal(root);
vector<int> res;
vector<pair<int, int>> vec(umap.begin(), umap.end());
sort(vec.begin(), vec.end(), cmp);
res.push_back(vec[0].first);
for (int i = 1; i < vec.size(); i ++) {
if (vec[i].second != vec[0].second) {
break;
}
res.push_back(vec[i].first);
}
return res;
}
};
236. 二叉树的最近公共祖先
class Solution {
public:
TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
if (root == q || root == p || root == nullptr) {
return root;
}
TreeNode* left = lowestCommonAncestor(root->left, p, q);
TreeNode* right = lowestCommonAncestor(root->right, p, q);
if (left != nullptr && right != nullptr) {
return root;
}
if (left == nullptr) {
return right;
}
else if (right == nullptr) {
return left;
}
else {
return nullptr;
}
}
};