Swift-数组中只出现一次的数字

题目:一个整型数组里除了两个数字之外，其他的数字都出现了两次。请找出这两个只出现一次的数字。要求时间复杂度是O(n)，空间复杂度是O(1).
核心代码:
<pre><code>`

// 1首次出现的位置
func indexOfOne(num:Int) -> Int {
    var number:Int = num
    var pos:Int = 1
    
    while (number & 1) == 0 {
        number = number >> 1
        pos += 1
    }
    
    return pos
}

func isNumberOfPos(num:Int,pos:Int) -> Bool {

// let temp:Int = 1 << (pos - 1)
// return (num & temp) == 0 ? false : true

    let number:Int = num >> (pos - 1)
    return (number & 1) == 1 ? true : false
}

func findNumberAppearOnce(arr:[Int]) -> (Int,Int) {
    
    var ORNum:Int = 0
    
    for i in 0..<arr.count {
        ORNum = ORNum ^ arr[i]
    }
    
    let position:Int = indexOfOne(num: ORNum)
    var first:Int = 0
    var second:Int = 0
    for i in 0..<arr.count {
        if  isNumberOfPos(num: arr[i], pos: position) {
            first = first ^ arr[i]
        } else {
            second = second ^ arr[i]
        }
    }
    return (first,second)
}`</code></pre>

测试代码:
<pre><code>var searchArr:[Int] = [2,4,4,7,3,2,5,5] var searchResult:(Int,Int) = searchNumber.findNumberAppearOnce(arr: searchArr) print("FlyElephant-\(searchArr)出现一次的两个数字---\(searchResult)")</code></pre>