使用 sparse clone 实现部分代码的拉取
假设我的项目目录是：
--test
--lib
--bin
--build
--src
现在我只想在服务器上拉取 build 目录下的东西。
$ mkdir pro1
$ cd pro1
$ git init
Initialized empty Git repository in E:/pro1/.git/
$ git remote add -f origin https://github.com/XXXXX/test.git #拉取remote的all objects信息
Updating origin
remote: Counting objects: 522, done.
remote: Compressing objects: 100% (383/383), done.
remote: Total 522 (delta 124), reused 508 (delta 110), pack-reused 0
Receiving objects: 100% (522/522), 566.56 KiB | 261.00 KiB/s, done.
Resolving deltas: 100% (124/124), done.
From https://github.com/XXXXX/test
* [new branch] master -> origin/master
$ git config core.sparsecheckout true #开启sparse clone
$ echo "build" >> .git/info/sparse-checkout #设置需要pull的目录，*表示所有，!表示匹配相反的
$ less .git/info/sparse-checkout
build
$ git pull origin master #拉取
$ ls
build
