基础
1.求1x2的20次方，并打印结果；
2.求1到100中，能被3或者7整除但是不能被21整除的的数的个数
sum1 = 0
for x in range(1, 101):
sum1 += x
avg1 = sum1 / 100
print('和：{}，平均值：{}'.format(sum1, avg1))
x = 0
sum2 = 0
while 1:
x += 1
sum2 += x
if x == 100:
break
avg2 = sum2 / x
print('和：{}，平均值：{}'.format(sum2, avg2))
sum3 = 0
for x in range(1, 101):
if x % 3 == 0:
sum3 += x
print('和：', sum3)
x = 1
sum4 = 0
while 1:
x += 1
if x % 3 == 0:
sum4 += x
elif x == 100:
break
print('和：', sum4)
sum5 = 0
for x in range(1, 101):
if x % 7 != 0:
sum5 += x
print('sum5和：', sum5)
x = 0
sum6 = 0
while 1:
x += 1
if x == 101:
break
elif x % 7 != 0:
sum6 += x
print('sum6和：', sum6)
提高
age = int(input('请输入年龄：'))
if age <= 0 or age >= 150:
print('年龄不合法')
elif age <= 8:
print('儿童')
elif age <= 16:
print('未年人')
elif age <= 35:
print('青壮年')
elif age <= 50:
print('中年')
else:
print('老年')
x = 1
for i in range(1,6):
x *= i
print(x)
x = 1
sum1 = 0
for i in range(1,21):
x *= i
sum1 += x
print(sum1)
x = 1
sum2 = 0
for i in range(1,21):
x *= i
sum2 += 1/x
print(sum2)
sum3 = 0
while 1:
x = int(input('请输入大于0的数:'))
if x == 0:
break
elif x > 0:
sum3 += x
else:
print('请输入大于0的数')
